f5數學顯兩條?20點

2011-01-07 3:22 am
1.by substituting(x^2+5x+!)^1/2=u,show 3x^2+15x+2(x^2+5x+1)^1/2can be reduced to 3u^2+2u-3
2.show that x^2+x+2x(x=2)^1/2=14
更新1:

sorry!should be2.show that x^2+x+2x(x=2)^1/2=(x+(x+2)^2)^2-2

更新2:

sorry!should be2.(x+(x+2)^(1/2))^2-2

更新3:

should be2.show that x^2+x+2x(x=2)^1/2=(x+(x+2)^2)^2-2

更新4:

sorry!these three delete should be2.show that x^2+x+2x(x=2)^1/2=(x+(x+2)^(1/2))^2-2

回答 (1)

2011-01-07 4:29 am
✔ 最佳答案
As follows:


圖片參考:http://i707.photobucket.com/albums/ww74/stevieg90/ScreenHunter_14Jan062028.gif


2011-01-06 22:19:13 補充:
Is that (x+(x+2)^(1/2))^2-2?? If so, I have done it.


收錄日期: 2021-04-22 00:53:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110106000051KK01010

檢視 Wayback Machine 備份