maths-circles(1)
2011-01-06 12:25 am
圖片參考：http://img440.imageshack.us/img440/6899/43586964.jpg
In the figure, chords AC and BD intersect at E. It is given that CE=8, BE=6, DE=12Prove that ⊿BEC~⊿AED.
回答 (1)
2011-01-06 12:42 am
✔ 最佳答案
∠CEB = ∠DEA (Vert. opp. ∠s)∠ECB = ∠EDA and ∠EBC = ∠EAD (∠s in the same segnemt)
Thus △BEC ~ △AED with x/6 = 12/8
So x = 9
參考: 原創答案
收錄日期: 2021-04-19 23:49:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110105000051KK00607