Indefinite Integration (20點!!)
回答 (1)
2011-01-05 5:28 am
✔ 最佳答案
∫ 2x / ((x^2)+1)ln((x^2)+1) dxNotice that [ln(x^2+1)]'=2x/(x^2+1). The original integration becomes
∫ 2x / ((x^2)+1)ln((x^2)+1) dx
=∫ 1 / ln((x^2)+1) d [ln(x^2+1)]
=ln[ln(x^2+1)] + C where C is a constant
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