1.(a+3)(a-3)
2.b*-4
3.25a*-b*c*
4.(xy-1)(xy+1)
5.(2x-3y-z)(-2-3y+z)
6.(a+4)*
7.9b*+12b+4
註*代表２次
數學(簡易多項的因式分解
2011-01-02 11:15 pm
回答 (2)
2011-01-03 11:39 am
✔ 最佳答案
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I guess the question no. 5 should be fixed as this :PHope it can help you!
參考: Factorized by myself
2011-01-03 12:12 am
1)(a+3)(a-3)已經OK了
2)b^2-4
=b^2-2^2
=(b+2)(b-2)
3)25a^2-b^2c^2
=(5a)^2-(bc)^2
=(5a+bc)(5a-bc)
4)(xy-1)(xy+1)已經OK了.
5)(2x-3y-z)(-2-3y+z)唔知你問咩
6)(a+4)^2都OK了
7)9b^2+12b+4
=(3b)^2+2(3b)(2)+2^2
=(3b+2)^2
2)b^2-4
=b^2-2^2
=(b+2)(b-2)
3)25a^2-b^2c^2
=(5a)^2-(bc)^2
=(5a+bc)(5a-bc)
4)(xy-1)(xy+1)已經OK了.
5)(2x-3y-z)(-2-3y+z)唔知你問咩
6)(a+4)^2都OK了
7)9b^2+12b+4
=(3b)^2+2(3b)(2)+2^2
=(3b+2)^2
參考: me
收錄日期: 2021-04-13 17:44:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110102000051KK00679