因式分解999^2=?
詳細列出過程,thanks
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因式分解999^2=?
2011-01-01 9:41 pm
回答 (3)
2011-01-06 7:29 am
✔ 最佳答案
(a-b)^2 = a^2 - 2ab + b^2999^2
=(1000-1) ^2
=1000^2 - 2(1000)(1) +1^2
=1000000-2000+1
=998001
2011-01-01 10:46 pm
如果我無記錯 因式分解喺將佢變成質因數連乘嘛
999 = 3 x 3 x 3 x 37
因為2次 姐系自乘多一次
999^2 = 999 x 999 = (3x3x3x37)x(3x3x3x37)
= 3x3x3x3x3x3x37x37
999 = 3 x 3 x 3 x 37
因為2次 姐系自乘多一次
999^2 = 999 x 999 = (3x3x3x37)x(3x3x3x37)
= 3x3x3x3x3x3x37x37
2011-01-01 9:52 pm
999^2 = (1000-1)^2 = 1000^2 - 2000+1 = 9998001
收錄日期: 2021-04-13 17:44:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110101000051KK00450