F.2 Maths quick!! 20points

2010-12-31 6:16 pm
factorization of polynomials
f.2

2(2x+y)2 – 6(2x+y)3= 2(2x+y)2 [1- 3(2x+y)]= _________________(answer)

thanks.
更新1:

...... to yuki nagato and larry, isn't it factorization..?? i mean... i don't relly know.. but i know that to double check the answer.. i need to calculate the answer and will get 2(2x+y)2 – 6(2x+y)3 back.. that means simplify is the opposite of factorization... .........

更新2:

i calculate back and calulate forth but i still got the same answer.. 2(2x+y)^2 – 6(2x+y)^3 = 2(2x+y) ^2 [1- 3(2x+y)] <------- = 2(2x+y) ^2 ( 1-6x-3y) = 2(2x+y) ^2 -6x[2(2x+y) ^2]- 3y [2(2x+y) ^2] = 2(2x+y) ^2 – 12x (2x+y) ^2 – 6y (2x+y) ^2 = (2-12x-6y) (2x+y) ^2 = 2((2x+y) ^2 [1- 3(2x+y)] <------

更新3:

oh no no no.. larry, you are right! XD

更新4:

oh nonono larry, u are right!! XD

回答 (2)

2010-12-31 6:54 pm
✔ 最佳答案
2(2x+y)2– 6(2x+y)3

= 2(2x+y)2 [1- 3(2x+y)

=2(2x+y)2( 1-6x-3y) (answer)


有錯請指正
參考: me
2010-12-31 6:27 pm
2(2x+y)2 – 6(2x+y)3
=2(4x2+y2)– 6(6x3+y3)
=(8x2+y2)–(36x3+y3)
=8x2+y2–36x3–y3

唔知有冇錯


收錄日期: 2021-04-19 23:46:54
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