Is 2x[5x+4(3x-5)] simplified (34x squared-40x)?

2x[5x+4(3x-5)]; distribute the 4 inside the brackets
2x[5x+12x-20]; add inside the bracket next
2x[17x-20]; remove brackets and use parenthesis
2x(17x-20); distribute the 2x through
34x^2-40x <------Answer

Yep it's right

Blessings

yes that ir correct. Fist u should find the answer of 4(3x-5)=> is 12x-20. Then sum the 5x with it. 5x+12x-20= 17x -20. Then 2x (17x-20)=34x^2 -40x

yes, your correct!

check it here..//
http://www.mathway.com/answer.aspx?p=calg?p=2xSMB085x+4(3x-5)SMB09SMB15?p=2?p=?p=?p=?p=?p=?p=?p=0?p=?p=

2x[5x+12x-20]
2x[17x-20]
34x^2 - 40x

TRUE ! CORRECT ! HEY TRUST YOURSELF !!!

yes

2x[5x + 4(3x - 5)]
= 2x[5x + 4(3x) - 4(5)]
= 2x[5x + 12x - 20]
= 2x[17x - 20]
= 2x(17x) - 2x(20)
= 34x^2 - 40x

Yes.

yup..it is 34x^2-40x

2x[5x + 4(3x - 5)]

Work inside out...

2x(5x + 12x - 20)

10x² + 24x² - 40x

34x² - 40x

Correct

i'm reli rubbish @ maths yet i think of it is how u initiate it.... you do long branch or d oda factorising way-properly, it tells you dat f(x)=5x(2x-a million)^3 n den it says show dat wen you upload 0.5 to it you may get (40x^3)(x+0.5) so what i did became i bigger f(x) which gave me 40x^4-20x^3+30x-5x then you definately might use (x+0.5) as a piece n attempt n divide it by that....[i think of.....] so: (40x^4-20x^3+30x-5x)/(x+0.5) [soz i'm reli rubish @ long branch, will go incorrect] yet, you need to get (40x^3)(x+0.5) interior the tip =]

2x[5x+4(3x-5)]

2 x (-20 + 17 x)