數學題…正變~

2010-12-30 5:13 am
解釋+答案+式

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謝謝!
更新1:

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回答 (2)

2010-12-30 5:28 am
✔ 最佳答案
(a) Let E = C + kN ( k is non-zero )

( 7500 x 4/3 ) = C + 300k ====> 300k + C = 10000 ----- (1)

( 12000 x 4/3 ) = C + 500k ====> 500k + C = 16000 ----- (2)

(2) - (1): 200k = 6000 k = 30

By (1): C = 16000 - 300( 30 ) = 1000

E = 1000 + 30N
============


(b) E = 4750 x 4 = 19000
19000 = 1000 + 30N
30N = 18000
N = 600

Hence, there are 600 participants
===========================

Hope I have helped you.
參考: Mathematics Teacher Mr. Ip
2010-12-30 5:24 am
E = C + pN, p 係常數
(3/4)(C + 300p) = 7500
C + 300p = 10000

(3/4)(C + 500p) = 12000
C + 500p = 16000

200p = 6000
p = 30
C = 10000 - 300(30) = 1000

E = 1000 + 30N
---------------------------
(1/4)(1000 + 30N) = 4750
N = 600


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