數學題…正變~

👨🏻‍🏫 學術台數學

愛

2010-12-30 5:13 am

解釋+答案+式

圖片參考：http://imgcld.yimg.com/8/n/HA01009730/o/701012290175013873433500.jpg

謝謝！

更新1:

http://f10.wretch.yimg.com/akpuser03/130/1353180104.jpg?hh8U5OxDdxNslPRpfv.DPoogfDVsXK6EDnJkJz6b0tbwlKXiREs_MQbdhWvsZXw-

回答 (2)

良師益友

2010-12-30 5:28 am

✔ 最佳答案

(a) Let E = C + kN ( k is non-zero )

( 7500 x 4/3 ) = C + 300k ====> 300k + C = 10000 ----- (1)

( 12000 x 4/3 ) = C + 500k ====> 500k + C = 16000 ----- (2)

(2) - (1): 200k = 6000 k = 30

By (1): C = 16000 - 300( 30 ) = 1000

E = 1000 + 30N
============

(b) E = 4750 x 4 = 19000
19000 = 1000 + 30N
30N = 18000
N = 600

Hence, there are 600 participants
===========================

Hope I have helped you.

參考: Mathematics Teacher Mr. Ip

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雞尾包

2010-12-30 5:24 am

E = C + pN, p 係常數
(3/4)(C + 300p) = 7500
C + 300p = 10000

(3/4)(C + 500p) = 12000
C + 500p = 16000

200p = 6000
p = 30
C = 10000 - 300(30) = 1000

E = 1000 + 30N
---------------------------
(1/4)(1000 + 30N) = 4750
N = 600

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