(x+2)(x+p) = x^2 -3x+q 求p、q值
(x+2)(x+p) = x^2 -3x+q 求p、q值
(x+2)(x+p) = x^2 -3x+q 求p、q值
(x+2)(x+p) = x^2 -3x+q 求p、q值
2010-12-29 6:10 am
回答 (1)
2010-12-29 6:13 am
✔ 最佳答案
L.H.S. = (x+2)(x+p) = x^2 + 2x + xp + 2p = x^2 + (2+p)x + 2pSo x^2 + (2+p)x + 2p = x^2 - 3x + q
Comparing coefficients,
2+p = -3
p = -5
2p = q
2(-5) = q
q = -10
參考: Knowledge is power.
收錄日期: 2021-04-25 17:10:47
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