differentiation
回答 (1)
2010-12-28 12:46 am
✔ 最佳答案
dy/dx = lim (h → 0) {[2(x + h) + 1/(x + h)2] - [2x + 1/x2]}/h= lim (h → 0) {[2(x + h) - 2x] + [1/(x + h)2 - 1/x2]}/h
= lim (h → 0) {[2h] + [x2 - (x + h)2]/[x2(x + h)2]}/h
= lim (h → 0) 2 + lim (h → 0) [-2hx - h2]/[hx2(x + h)2]
= 2 - lim (h → 0) [2x - h]/[x2(x + h)2]
= 2 - 2x/x4
= 2 - 2/x3
參考: 原創答案
收錄日期: 2021-04-19 23:44:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101227000051KK00780