1) If k is a real number, then 4k-(6+ki)/i = ?
2) Peter invests $P at the beginning of each month in a year at an interest rate of 6% per annum, compounded monthly. If he gets $10000 at the end of the year, find P correct to 2 decimal places.
please show the steps.
maths questions
2010-12-25 10:41 pm
回答 (1)
2010-12-26 5:37 am
✔ 最佳答案
1) 4k-(6+ki)/i = 4k - 6/i + ki/i=4k -6/i +k
=5k - 6/i
2)
r = 6% /12 = 0.005, n = 12 months
Principal with interest ($10000) = P x [(1+r)^n - 1] / r
10000 = P (1.005^12 - 1) / 0.005
=810.66
收錄日期: 2021-04-13 17:43:36
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