what is the difference between these two equations and explain briefly.
1. 2H2SO4(l) + 2e- -> SO42-(aq) + SO2 (g) + 2H2O(l)
2. H2SO4(l) + 2H+(aq) + 2e- ->/<- (reverse) SO2 (g) + 2H2O(l)
sulphuric acid
2010-12-25 7:35 am
回答 (2)
2010-12-28 2:19 am
✔ 最佳答案
those equations are wrong. it should be :H2SO4+2H(+)+2E=SO2+H2O
參考: me
2011-01-03 9:22 am
1. 2H2SO4 + 2e- <======> SO4(2-) + SO2 + 2H2O
2. H2SO4 + 2H(+) + 2e(-) <======> SO2 + 2H2O
3. SO4(2-) + 4H(+) + 2e(-) <======> SO2 + 2H2O
2011-01-03 01:23:44 補充：
there's almost no difference.
the protons still come from sulphuric acid.
the sulphate ion in equation 1 doesn't take part in reaction, so it can be ignored.
2011-01-03 01:24:00 補充：
kai fung, YOUR equation is Wrong. your no. of hydrogens cannot balance!!
left: 4, right: 2
also, the symbol of electron is e-, not "E".
2. H2SO4 + 2H(+) + 2e(-) <======> SO2 + 2H2O
3. SO4(2-) + 4H(+) + 2e(-) <======> SO2 + 2H2O
2011-01-03 01:23:44 補充：
there's almost no difference.
the protons still come from sulphuric acid.
the sulphate ion in equation 1 doesn't take part in reaction, so it can be ignored.
2011-01-03 01:24:00 補充：
kai fung, YOUR equation is Wrong. your no. of hydrogens cannot balance!!
left: 4, right: 2
also, the symbol of electron is e-, not "E".
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