✔ 最佳答案
|a| = |b| = |a + b|
|a|2 = |b|2 = |a + b|2
a . a = b . b = (a + b ) . (a + b )
a . a = a . a + b . b + 2 a . b 和 b . b = a . a + b . b + 2 a . b
0 = b . b + 2 a . b 和 0 = a . a + 2 a . b
所以, 假設 |a| = |b| = k 和 夾角為 x:
k2 + 2k2 cos x = 0
cos x = -1/2
x = 120 度