✔ 最佳答案
∠CAB=45 (diagonal of square)
∠C'AB=45+15=60 (C is rotated 15 about A)
Consider the triangle ACC',
∠C'AC=∠C'AB-∠CAB=60-45=15
triangle ACC' is isoceles (since AC=AC')
∠C'CA=(180-∠C'AC)/2=(180-15)/2=82.5(∠ sum of triangle)
∠CC'B=∠C'CA+∠ACB=82.5+45=127.5
2010-12-19 19:51:01 補充:
sorry...
∠CC'B'
=∠CC'A-∠AC'B'
=82.5-45
=37.5
I have calculated ∠C'CB..