2. Factorize m-n-(n-m)^2
請附 詳細 步驟。
更新1:
Sorry, I type No. 1 wrongly. It is 1. Factorize (3x-2y)(a^2+2b)+(2b-a^2)(2y-3x)
中二級數學題（因式分解）
2010-12-18 9:46 pm
1. Factorize (3x-3y)(a^2+2b)+(2b-a^2)(2y-3x)
2. Factorize m-n-(n-m)^2
請附 詳細 步驟。
2. Factorize m-n-(n-m)^2
請附 詳細 步驟。
回答 (3)
2010-12-19 1:07 am
✔ 最佳答案
1. Factorize (3x-2y)(a^2+2b)+(2b-a^2)(2y-3x) =(3x-2y)(a^2+2b)-(3x-2y)(2b-a^2)
=(3x-2y)[(a^2+2b)-(2b-a^2)]
=(3x-2y)2a^2
=2a^2(3x-2y)
2. Factorize m-n-(n-m)^2
=-(n-m)-(n-m)^2
=-(n-m)[1+(n-m)]
=(m-n)(1+n-m)
2010-12-18 11:16 pm
As a small reminder,
-(a² +2b) = (-a²-2b)
2010-12-18 15:17:35 補充：
Maybe the questioner's question
is Factorize (3x-3y)(a^2+2b)+(2b-a^2)(3y-3x)
or Factorize (3x-2y)(a^2+2b)+(2b-a^2)(2y-3x) <--- then they can be easier to factorise
-(a² +2b) = (-a²-2b)
2010-12-18 15:17:35 補充：
Maybe the questioner's question
is Factorize (3x-3y)(a^2+2b)+(2b-a^2)(3y-3x)
or Factorize (3x-2y)(a^2+2b)+(2b-a^2)(2y-3x) <--- then they can be easier to factorise
2010-12-18 10:54 pm
1. (3x-3y)(a² +2b) + (2b-a² )(2y-3x)= -(3y-3x)(a² +2b) + (2b-a² )(2y-3x)= (3y-3x)(2b-a² ) + (2b-a² )(2y-3x)= (2b-a² )(3y-3x+2y-3x)= (2b-a² )(5y-6x) or (a² -2b)(6x-5y)// 2. m-n-(n-m)²
= -(n-m)- (n-m)²
= (n-m)(-1-(n-m))= (n-m)(-1-n+m)= (n-m)(m-n-1)//
Hope this help!
= -(n-m)- (n-m)²
= (n-m)(-1-(n-m))= (n-m)(-1-n+m)= (n-m)(m-n-1)//
Hope this help!
參考: Myself
收錄日期: 2021-04-23 22:10:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101218000051KK00470