TAKE RIGHTWARD IS POSITIVE.
A trolley (have a mass of 2kg) is placed on the floor.
A force F is acting on the trolley.
The acceleration of the trolley is 3ms^-2.
Find the magnitude of the friction f between the floor and the trolley.
PLEASE SHOWS STEPS AND EXPLAIN BRIEFLY.
物理URGENT
2010-12-17 11:33 pm
回答 (2)
2010-12-18 3:46 am
✔ 最佳答案
Take rightward diretion to be +ve.Hence, net force acting on the trolley = F + (-f) = F - f
Since net-force = mass x acceleration,
thus, F - f = 2 x 3
i.e. f = F - 6
The frictional force is thus 6 N smaller than the applied force F.
2010-12-18 1:43 am
F - f = ma = 6
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