最好用let u 黎做 唔好跳咁多步
更新1:
=∫[2/(1+3x)] dx - ∫ [4/(1-3x)^2] dx點變=(2/3)∫[1/(1+3x)] d(1+3x) + (4/3)∫ [1/(1-3x)^2] d(1-3x) 點解會除3?
integration
回答 (1)
2010-12-14 2:28 am
✔ 最佳答案
∫{[ 2/(1+3x)] - [ 4/(1-3x)^2]} dx=∫[2/(1+3x)] dx - ∫ [4/(1-3x)^2] dx
=(2/3)∫[1/(1+3x)] d(1+3x) + (4/3)∫ [1/(1-3x)^2] d(1-3x)
=(2/3)ln(1+3x) - (4/3)[1/(1-3x)] + C
收錄日期: 2021-04-19 23:41:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101213000051KK00921