[急]1元1次方程!!!!幫下Me

1) x+6/6 - (x-1)=x-3/3 - x+2/2(x+6)/6 - (x-1) = (x-3)/3 - (x+2)/2(x+6) - 6(x-1) = 2(x-3) - 3(x+2)x+6 - 6x+6 = 2x-6 - 3x-6- 5x + 12 = - x - 124x = 24x = 6
2) 3(x+1) - 1/3(x-1)=2(x-1) - 1/2(x+1)3(x+1) - (1/3)(x-1)=2(x-1) - (1/2)(x+1)18(x+1) - 2(x-1) = 12(x-1) - 3(x+1)18x+18 - 2x+2 = 12x-12 - 3x-316x + 20 = 9x - 157x = - 35x = - 5
3) 2[4/3 x - (2/3 x - 1/2)]=3/4 x2{(4/3) x - [(2/3)x - 1/2)]} = (3/4) x2 [ 16x - (8x - 6) ] = 9x2 (8x + 6) = 9x16x + 12 = 9x7x = - 12x = - 12/7
4) 0.1x-0.2/0.02 - x+1/0.5=3(0.1x - 0.2)/0.02 - (x+1)/0.5 = 3(5x - 10) - 2(x + 1) = 35x - 10 - 2x - 2 = 33x = 15x = 5
5) x-3/2[x - 2/3(x - 2/3)]=2/3x - (3/2)[x - (2/3)(x - 2/3)] = 2/3x - [(3/2)x - (x - 2/3)] = 2/36x - [9x - (6x - 4)] = 46x - 9x + 6x - 4 = 43x = 8x = 8/3