請師兄師姐幫我解答以下 Phy 問題, 謝謝
A heart defibrillator was charged by a 9.0 kV voltage source.
The energy stored was 500 J.
Find the capacitance and the amount of stored charges.
AL Phy
2010-12-08 6:52 pm
回答 (1)
2010-12-08 7:11 pm
✔ 最佳答案
From E=(1/2)CV^2,500=(1/2)C(9.0x10^3)^2
C=12.3μF
The capacitance is 12.3μF
From Q=CV,
Amount of stored charges
=(12.3x10^-6)(9x10^3)
=0.111C
The amount of stored charges is 0.111C
收錄日期: 2021-04-13 17:41:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101208000051KK00259