圖片參考：http://img80.imageshack.us/img80/6385/laplaceu0.jpg
更新1:
謝謝喔!* 仲有哪些情況不能用formula...!? (簡單的"情況")
laplace transform U(t-1)
回答 (2)
2010-12-08 4:12 am
✔ 最佳答案
L[e^t U(t-1)]=∫ (e^t)(e^(-st))dt [from 1 to infinity]
=∫ e^[-(s-1)t] dt [from 1 to infinity]
=-e^[-(s-1)]/(s-1)
所以最後負負得正。就我所知就一個函數和一個階梯函數的乘積﹐是沒有公式套用的﹐每次都要親自計。
2010-12-08 6:11 am
L{ f(t-p) u(t-p) } = e^(-ps) F(s)
The positive sign is obviously a mistake.
The positive sign is obviously a mistake.
收錄日期: 2021-04-23 23:24:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101207000051KK00925