2. Find vector equation of the tangent line at the point (-2,2,4) to the courve of the intersection of thre surface z-2x^2 - y^2 and the plane z=4.
更新1:
1. Find a vector equation of the line tangent to the graph of r(t) = (t^2) i - (1/(t+1)) j +(4-(t^2)) k at the point (4,1,0) on the curve. 2. Find vector equation of the tangent line at the point (-2,2,4) to the curve of the intersection of thre surface z=2x^2 - y^2 and the plane z=4.
更新2:
1. 點解知道代t=-2?? 係咪要令到r'(t)//r(t)???點知佢地平衡??
更新3:
平行 ......
更新4:
2.my standard answer is r(t)=(-2,2,4)+t(1,-2,0) 我都唔係好明點搵vector equation of tangent , 係咪好似第一題咁 (4,1,0) + s(-4,1,4)??? 第二題就 (-2,2,4)+s(-2,4,0)????
