1)B=a/2+c2次方/3 求當a=4及c=6時b的值
2)y=a2次方+b2次方+c2次方 求當a=1 b=2 及c=3時y的值
3)a=b-2cd [c]
中2數學功課 有3題 今日之內有答案 送10分
2010-11-28 7:33 pm
回答 (6)
2010-11-28 7:41 pm
✔ 最佳答案
B=a/2+c^2/3B=(4/2)+(6)^2/3
B=2+12
B=14
_______________
y=a^2+b^2+c^2
y=(1)^2+(2)^2+(3)^2
y=14
__________________
a=b-2cd [c]
a-b=-2cd
c=(a-b)/-2d
c=(b-a)/2d
______________
2010-11-28 11:41:28 補充：
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參考: , 魔龍帝齊格益力多
2010-12-08 3:53 am
1) B=a/2+(C^2)/3
=4/2+(6^2) /3
=2+36/3
=2+12
=14
2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14
3) a=b-2cd
2cd=b-a
c=(b-a)/2d
=4/2+(6^2) /3
=2+36/3
=2+12
=14
2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14
3) a=b-2cd
2cd=b-a
c=(b-a)/2d
2010-11-29 5:34 am
1.
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 2+4
b = 6
2.
y = a^2+b^2+c^2
sub a=1, b=2 and c=3
y = 1^2+2^2+3^2
y = 1+4+9
y = 14
3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/2d
2010-11-28 21:35:45 補充：
3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/(2d) <== 分母漏了( )
2010-11-28 21:36:43 補充：
1.
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 4/2 + 36/3 <== sorry,上面寫錯左
b = 2+12
b = 14
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 2+4
b = 6
2.
y = a^2+b^2+c^2
sub a=1, b=2 and c=3
y = 1^2+2^2+3^2
y = 1+4+9
y = 14
3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/2d
2010-11-28 21:35:45 補充：
3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/(2d) <== 分母漏了( )
2010-11-28 21:36:43 補充：
1.
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 4/2 + 36/3 <== sorry,上面寫錯左
b = 2+12
b = 14
參考: girl
2010-11-29 2:53 am
1) B=a/2+c^2/3
B=(4/2)+(6)^2/3
B=2+12
B=14
2) y=a^2+b^2+c^2
y=(1)^2+(2)^2+(3)^2
y=14
3) a=b-2cd [c]
a-b=-2cd
c=(a-b)/-2d
c=(b-a)/2d
B=(4/2)+(6)^2/3
B=2+12
B=14
2) y=a^2+b^2+c^2
y=(1)^2+(2)^2+(3)^2
y=14
3) a=b-2cd [c]
a-b=-2cd
c=(a-b)/-2d
c=(b-a)/2d
參考: myself:)
2010-11-28 8:52 pm
1) B=a/2+(C^2)/3
=4/2+(6^2) /3
=2+36/3
=2+12
=14
2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14
3) a=b-2cd
2cd=b-a
c=(b-a)/2d
=4/2+(6^2) /3
=2+36/3
=2+12
=14
2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14
3) a=b-2cd
2cd=b-a
c=(b-a)/2d
2010-11-28 7:45 pm
1.B=14
2.y=14
3.唔知你問咩
2.y=14
3.唔知你問咩
收錄日期: 2021-04-23 23:21:55
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