中2數學功課有3題今日之內有答案送10分

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[匿名]

2010-11-28 7:33 pm

1)B=a/2+c2次方/3 求當a=4及c=6時b的值

2)y=a2次方+b2次方+c2次方求當a=1 b=2 及c=3時y的值

3)a=b-2cd [c]

回答 (6)

魔龍帝齊格益力多

2010-11-28 7:41 pm

✔ 最佳答案

B=a/2+c^2/3
B=(4/2)+(6)^2/3
B=2+12
B=14
_______________
y=a^2+b^2+c^2
y=(1)^2+(2)^2+(3)^2
y=14
__________________
a=b-2cd [c]
a-b=-2cd
c=(a-b)/-2d
c=(b-a)/2d
______________

2010-11-28 11:41:28 補充：
.

參考: , 魔龍帝齊格益力多

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[匿名]

2010-12-08 3:53 am

1) B=a/2+(C^2)/3
=4/2+(6^2) /3
=2+36/3
=2+12
=14

2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14

3) a=b-2cd
2cd=b-a
c=(b-a)/2d

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用戶22403

2010-11-29 5:34 am

1.
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 2+4
b = 6

2.
y = a^2+b^2+c^2
sub a=1, b=2 and c=3
y = 1^2+2^2+3^2
y = 1+4+9
y = 14

3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/2d

2010-11-28 21:35:45 補充：
3.
a = b-2cd [c]
2cd = b-a
c = (b-a)/(2d) <== 分母漏了( )

2010-11-28 21:36:43 補充：
1.
b = a/2 + c^2/3
sub a=4 and c=6
then, b = 4/2 + 6^2/3
b= 4/2 + 36/3 <== sorry,上面寫錯左
b = 2+12
b = 14

參考: girl

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[匿名]

2010-11-29 2:53 am

1) B=a/2+c^2/3
B=(4/2)+(6)^2/3
B=2+12
B=14

2) y=a^2+b^2+c^2
y=(1)^2+(2)^2+(3)^2
y=14

3) a=b-2cd [c]
a-b=-2cd
c=(a-b)/-2d
c=(b-a)/2d

參考: myself:)

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[匿名]

2010-11-28 8:52 pm

1) B=a/2+(C^2)/3
=4/2+(6^2) /3
=2+36/3
=2+12
=14

2) y=a^2+b^2+c^2
=1^2+2^2+3^2
=2+36/3
=14

3) a=b-2cd
2cd=b-a
c=(b-a)/2d

👍 0 👎 0