Permutation
2010-11-25 6:08 am
For 6 red balls and 4 green balls, find the permutation of selecting any 8 balls.
回答 (2)
2010-11-25 7:07 am
✔ 最佳答案
4 red balls and 4 green balls= 8! / [(4!)(4!)] = 70 ways5 red balls and 3 green balls= 8! / [(5!)(3!)] = 56 ways
6 red balls and 2 green balls= 8! / [(6!)(2!)] = 28 ways
Total 70 + 56 + 28 = 154 ways
2010-11-25 8:16 am
permutation ?
收錄日期: 2021-04-21 22:17:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101124000051KK01339