數學上的問題 圓形

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圖片參考：http://img146.imageshack.us/img146/6567/circle3.png


2010-11-24 23:55:56 補充：
http://img146.imageshack.us/img146/6567/circle3.png

2010-11-25 00:05:59 補充：
sorry, x=0, but x cannot be any other numbers,
x should be lie on the line perpendicular bisect the line passing through (2,2) and (-2,-2)

2010-11-25 00:18:01 補充：
slope of the line =2-(-2)/2-(-2) =4/4 =1
slope of line perpendicular to this line =-1
point which bisect the line =( (2-2)/2 , (2-2)/2) =(0,0)

centre of the circle can be any point lie on the line:
(y-0)/(x-0)=-1
y/x=-1
y=-x

e.g. centre of the circle can be (1,-1) (2,-2) (-3,3)

2010-11-25 16:38:51 補充：
更正更正, for centre (x, y) of the circle which pass through the 2 points,
x can be any other numbers which
satisfy the equation of stright line y=-x
e.g. centre of the circle can be (0,0) , (-1,1),(1,-1),(2,-2),(-2,2),(-2.5, 2.5)