math m2

👨🏻‍🏫 學術台數學

[匿名]

2010-11-24 5:34 am

1. lt is given that (2+5x)6次方=a+bx+cx2次+terms involving higher powers of x, find the values of a, b and c.

回答 (3)

用戶2053

2010-11-24 5:41 am

✔ 最佳答案

(2+5x)^6= 2^6 + (6C1)(2^5)(5x) + (6C2)(2^4)(5x)^2 + ... + (5x)^6= 64 + 960x + 6000x^2 + ... + (5x)^6a = 64b = 960c = 6000

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William

2010-11-28 7:27 am

咪玩啦dickzxcv,改少少就當答咗
而且字體唔同

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[匿名]

2010-11-24 5:58 am

(2+5x)^6= 6次方2 + (6C1)(5次方2)(5x) + (6C2)(4次方2)(5x)2次方 + ... + (5x)6次方= 64 + 960x + 6000x2次方 + ... + (5x)6次方a = 64b = 960c = 6000

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