數學因式分解
回答 (3)
2010-11-24 4:30 am
✔ 最佳答案
ax + ay - 3bx^2 + 3by^2= a(x + y) - 3b(x^2 - y^2)= a(x + y) - 3b(x - y)(x + y)= (x + y)[a - 3b(x - y)]or= (x + y)(a - 3bx - 3by)2010-11-23 20:45:51 補充：
(x + y)(a - 3bx - 3by) should be (x + y)(a - 3bx + 3by)
2010-11-24 8:54 am
ax+ay-3bx二次方+3by二次方=a(x+y)-3b(x的二次方-y的二次方)= a(x+y)-3b(x+y)(x-y)=(x+y)(a-3bx+3by)
2010-11-24 5:03 am
ax+ay-3bx二次方+3by二次方
= ax+ay-3bx^2+3by^2
= a(x+y) - 3b(x^2-y^2)
= a(x+y) - 3b(x+y)(x-y)
= (x+y) [a-3b(x-y)]
= ax+ay-3bx^2+3by^2
= a(x+y) - 3b(x^2-y^2)
= a(x+y) - 3b(x+y)(x-y)
= (x+y) [a-3b(x-y)]
參考: girl
收錄日期: 2021-04-21 22:17:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101123000051KK01101