System of Equations

2010-11-23 4:05 am
Could anyone please teach me how to solve the following system of equations?

-x^2-(y-1)^2+1<=0
2(1-z)x=0
-2z(y-1)-cos(y)=0
z(-x^2-(y-1)^2+1)=0
z>=0
-2<=y<=2 (radian)
x,z are real numbers

It seems that there are a lot of possible solutions before using the inequality to do the rejection, how can we avoid missing any possible solutions?
Please give me some explanations if it is possible.
Thanks!

回答 (1)

2010-11-23 5:08 am
✔ 最佳答案
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2010-11-22 21:08:42 補充:
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