1/(y-z)(x-y) + 1/(y-x)(x-z)
唔識計,找人幫手解答依個maths題
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Maths題,急急急
2010-11-21 3:40 am
回答 (3)
2010-11-21 4:59 am
✔ 最佳答案
你好～～～我想你的問題應該如下吧︰
1 / [(y - z)(x - y)] + 1 / [(y - x)(x - z)]
= 1 / [(y - z)(x - y)] + 1 / [-(x - y)(x - z)
= 1 / [(y - z)(x - y)] - 1 / [(x - y)(x - z)]
= (x - z) / [(y - z)(x - y)(x - z)] - (y - z) / [(y - z)(x - y)(x - z)]
= [(x - z) - (y - z)] / [(y - z)(x - y)(x - z)]
= (x - y) / [(y - z)(x - y)(x - z)]
= 1 / [(y - z)(x - z)
希望以上解答可以幫到你～～～～～
2010-11-20 21:00:06 補充：
= 1 / [(y - z)(x - z)]
溜了最後一個符號。。
2010-11-21 17:09:21 補充：
Jolin 又抄我……
你少左最後那個符號呀～～～
參考: Yogi
2010-11-21 10:17 pm
1 / [(y - z)(x - y)] + 1 / [(y - x)(x - z)]
= 1 / [(y - z)(x - y)] + 1 / [-(x - y)(x - z)
= 1 / [(y - z)(x - y)] - 1 / [(x - y)(x - z)]
= (x - z) / [(y - z)(x - y)(x - z)] - (y - z) / [(y - z)(x - y)(x - z)]
= [(x - z) - (y - z)] / [(y - z)(x - y)(x - z)]
= (x - y) / [(y - z)(x - y)(x - z)]
= 1 / [(y - z)(x - z)
= 1 / [(y - z)(x - y)] + 1 / [-(x - y)(x - z)
= 1 / [(y - z)(x - y)] - 1 / [(x - y)(x - z)]
= (x - z) / [(y - z)(x - y)(x - z)] - (y - z) / [(y - z)(x - y)(x - z)]
= [(x - z) - (y - z)] / [(y - z)(x - y)(x - z)]
= (x - y) / [(y - z)(x - y)(x - z)]
= 1 / [(y - z)(x - z)
參考: me
收錄日期: 2021-04-23 22:41:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101120000051KK01318