1a)c^2+7c-8
1b)-x^6-7x^3+8
中三級數學科因式分解問題
2010-11-19 1:40 am
回答 (4)
2010-11-19 2:02 am
✔ 最佳答案
1a)c^2+7c-8= (c+8)(c-1)
1b)-x^6-7x^3+8
= -(x^6 + 7x^3 - 8)
= -(x^3 + 8)(x^3 - 1)
= -(x+2)(x^2 - 2x + 4)(x-1)(x^2 + x + 1)
參考: Hope the solution can help you^^”
2010-11-22 12:10 am
1a) c^2+7c-8
=(c-1)(c+8)
1b) -x^6-7x^3+8,same as 1a),please look at these solution:
Solution
-x^6-7x^3+8
=-1(x^6+7x^3+8)
=-1(x^3-1)(x^3+8)
=(c-1)(c+8)
1b) -x^6-7x^3+8,same as 1a),please look at these solution:
Solution
-x^6-7x^3+8
=-1(x^6+7x^3+8)
=-1(x^3-1)(x^3+8)
2010-11-19 4:52 am
1a)
c^2+7c-8
= (c+8)(c-1)
1b)
let x^3 = c
-x^6-7x^3+8
= -[(x^3)^2+7x^3-8]
= -(x^3+8)(x^3-1)
c^2+7c-8
= (c+8)(c-1)
1b)
let x^3 = c
-x^6-7x^3+8
= -[(x^3)^2+7x^3-8]
= -(x^3+8)(x^3-1)
參考: girl
2010-11-19 1:44 am
1a)c^2+7c-8
=(c-7)(c-1)
=(c-7)(c-1)
收錄日期: 2021-04-23 23:13:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101118000051KK00876