1.試以x表示y.
1-x/x = n+y/y
2.試以y表示x.
n+y/y = 1-x/x
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2010-11-18 6:24 am
回答 (4)
2010-11-18 10:19 pm
1.試以x表示y.
1-x/x = n+y/y
xn+xy=y-xy
xn+2xy=y
x(x+2y)=y
x=y/(x+2y)
2.試以y表示x.
n+y/y = 1-x/x
y-xy=xn+xy
y(1-x-x)=xn
y=xn/(1-2x)
1-x/x = n+y/y
xn+xy=y-xy
xn+2xy=y
x(x+2y)=y
x=y/(x+2y)
2.試以y表示x.
n+y/y = 1-x/x
y-xy=xn+xy
y(1-x-x)=xn
y=xn/(1-2x)
參考: i am teacher
2010-11-18 7:48 am
1.
1-x/x = n+y/y
(1-x)/x = (n+y)/y
y(1-x) = x(n+y)
y-xy = xn+xy
y = xn+xy+xy
y = xn+2xy
y=x(n+2y)
x = y / (n+2y)
2.
n+y/y = 1-x/x
(n+y)/y = (1-x)/x
x(n+y) = y(1-x)
xn+xy = y-xy
xn = y-xy-xy
xn = y-2xy
xn = y(1-2x)
y = (xn) / (1-2x)
2010-11-17 23:49:56 補充：
OH NO.....
我把兩題答案倒轉左.....
1-x/x = n+y/y
(1-x)/x = (n+y)/y
y(1-x) = x(n+y)
y-xy = xn+xy
y = xn+xy+xy
y = xn+2xy
y=x(n+2y)
x = y / (n+2y)
2.
n+y/y = 1-x/x
(n+y)/y = (1-x)/x
x(n+y) = y(1-x)
xn+xy = y-xy
xn = y-xy-xy
xn = y-2xy
xn = y(1-2x)
y = (xn) / (1-2x)
2010-11-17 23:49:56 補充：
OH NO.....
我把兩題答案倒轉左.....
參考: girl
2010-11-18 7:04 am
吾=>"我"的意思
吾識做=>"我"識做..
咁仲黎問乜
吾識做=>"我"識做..
咁仲黎問乜
2010-11-18 6:38 am
1.
(1-x)/x = (n+y)/y
y(1-x) = (n+y)x
y-xy=nx+xy
y-2xy = nx
y(1-2x)=nx
y=nx/(1-2x)
2.
(1-x)/x = (n+y)/y
y(1-x) = (n+y)x
y-xy=nx+xy
y=nx+2xy
y=x(n+2y)
x=y/(n+2y)
(1-x)/x = (n+y)/y
y(1-x) = (n+y)x
y-xy=nx+xy
y-2xy = nx
y(1-2x)=nx
y=nx/(1-2x)
2.
(1-x)/x = (n+y)/y
y(1-x) = (n+y)x
y-xy=nx+xy
y=nx+2xy
y=x(n+2y)
x=y/(n+2y)
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