如題,,請例出步驟~
1.y^(-4/3)•(1/27y)^2/3
2.2√x乘x^3/4除x^-3
3.(2a)^2/3乘√a/2
有關指數既問題~!!!!!!!(20點)
2010-11-16 4:02 am
回答 (3)
2010-11-16 5:12 am
答案:
1.
y^(-4/3)×(y/27)^(2/3)
=1/y^(4/3) ×y^(2/3)/9
=y^(2/3-4/3)/9
=y^(-2/3)/9
=1/(9y^(2/3) )
2.
2√x×x^(3/4)/x^(-3)
=2x^(1/2)×x^(3/4-(-3))
=2x^(1/2+15/4)
=2x^(17/4)
3.
(2a)^(2/3)×√a/2
=2^(2/3)×a^(2/3)×a^(1/2)/2
=a^(1/2+2/3) 2^(2/3-1)
=a^(7/6)/2^(1/3)
1.
y^(-4/3)×(y/27)^(2/3)
=1/y^(4/3) ×y^(2/3)/9
=y^(2/3-4/3)/9
=y^(-2/3)/9
=1/(9y^(2/3) )
2.
2√x×x^(3/4)/x^(-3)
=2x^(1/2)×x^(3/4-(-3))
=2x^(1/2+15/4)
=2x^(17/4)
3.
(2a)^(2/3)×√a/2
=2^(2/3)×a^(2/3)×a^(1/2)/2
=a^(1/2+2/3) 2^(2/3-1)
=a^(7/6)/2^(1/3)
2010-11-16 4:35 am
sol
把分母中的根号化去，叫做分母有理化。
y^(-4/3)×(y/27)^(2/3)
=1/y^(4/3) ×y^(2/3)/9
=y^(2/3-4/3)/9
=y^(-2/3)/9
=1/(9y^(2/3) )
2.2√x×x^(3/4)/x^(-3)
=2x^(1/2)×x^(3/4-(-3))
=2x^(1/2+15/4)
=2x^(17/4)
3.(2a)^(2/3)×√a/2
=2^(2/3)×a^(2/3)×a^(1/2)/2
=a^(1/2+2/3) 2^(2/3-1)
=a^(7/6)/2^(1/3)
2010-11-15 20:36:01 補充：
it seems that he's form3
把分母中的根号化去，叫做分母有理化。
y^(-4/3)×(y/27)^(2/3)
=1/y^(4/3) ×y^(2/3)/9
=y^(2/3-4/3)/9
=y^(-2/3)/9
=1/(9y^(2/3) )
2.2√x×x^(3/4)/x^(-3)
=2x^(1/2)×x^(3/4-(-3))
=2x^(1/2+15/4)
=2x^(17/4)
3.(2a)^(2/3)×√a/2
=2^(2/3)×a^(2/3)×a^(1/2)/2
=a^(1/2+2/3) 2^(2/3-1)
=a^(7/6)/2^(1/3)
2010-11-15 20:36:01 補充：
it seems that he's form3
參考: Google 計算機的更多資料
2010-11-16 4:08 am
Which Form are you in?
收錄日期: 2021-04-23 19:22:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101115000051KK01310