想問下 2700 / (1+R) + 3200 / (1+R)^2 = 4000
R點求? 唔該
中學數學題
2010-11-15 8:35 pm
回答 (1)
2010-11-15 9:56 pm
✔ 最佳答案
2700 / (1+R) + 3200 / (1+R)^2 = 400027 / (1+R) + 32 / (1+R)^2 = 4027(1+R) + 32 = 40(1+R)^240(1+R)^2 - 27(1+R) - 32 = 0(1+R) = {-(-27) ± √[(-27)^2 - 4(40)(-32)] } / (2*40)1+R = (27 ± √5849) / 80R = (- 53 ± √5849) / 80R = 0.29348 or R = - 1.61848
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101115000051KK00528