數學嘅因式分解問題~`

2010-11-13 1:05 am
cd(l²+1)-l(c²+d²)
更新1:

呢個題目我知最後答案係''(lc-d)(ld-c) 但唔識計~~要比步驟

回答 (2)

2010-11-13 1:12 am
✔ 最佳答案
cd(l²+1) - l(c²+d²)= cdl² + cd - lc² - ld²= (cdl² - ld²) + (cd - lc²)= dl(cl - d) + c(d - cl)= dl(cl - d) - c(cl - d)= (dl - c) (cl - d)


2010-11-13 16:06:50 補充:
(dl - c) (cl - d)

= (lc - d) (ld - c) , 只是次序問題,排一排就對了。
2010-11-13 1:16 am
cd(l²+1)-l(c²+d²)=(cdl²+cdl²)-(lc²+ld²)
=cdl²+cdl²-lc²-ld²
=2cdl²-lc²-ld²
=2d-ld²
=2-l
i dont know the excact answer,but i think the first three line are correct.


收錄日期: 2021-04-21 22:16:12
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