數學三角函數
回答 (2)
2010-11-13 6:53 am
✔ 最佳答案
sinθ-cosθ＝1/3 兩邊平方(sinθ)^2-2*sinθ*cosθ+(cosθ)^2=1/9
1-2*sinθ*cosθ=1/9
-2*sinθ*cosθ=-8/9
sinθ*cosθ=4/9
題目可能應該是
secθ-cscθ
=(1/cosθ)-(1/sinθ)
=(sinθ-cosθ)/(sinθ*cosθ)
=(1/3)/(4/9)
=(1/3)*(9/4)
=3/4
2010-11-13 1:03 am
sinθ - cosθ = 1/3
sin 58.633 - cos 58.633 = 1/3
So θ = 58.633°
sec 58.633 - cos 58.633 = 0.65065 not 3/4
Your answer is wrong.
sin 58.633 - cos 58.633 = 1/3
So θ = 58.633°
sec 58.633 - cos 58.633 = 0.65065 not 3/4
Your answer is wrong.
收錄日期: 2021-04-21 22:16:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101112000016KK03788