Velocities and Directions

2010-11-11 1:43 am
A helium ballon and its gondola , of mass M, are in the air and stationary with respect to the ground . A passenger , of mass m , then climbs out and slides a rope with the speed of v , measured wit respect to the ballon. With what speeds and direction ( relative to Earth) does the balloon then moves? what happens of the passengers stops?
更新1:

An extra proof of the centre of mass of the system of the momentum is conserved will make me feel better.

回答 (1)

2010-11-11 8:40 pm
✔ 最佳答案
Since the centre of mass of the system (balloon and passenger) would not move, the downward momentum of the passenger equals to the upward momentum of the balloon. Hence,mv = (M-m)Vwhere V is the upward velocity of the balloon.i.e. V = mv/(M-m) If the passenger stops climbing, the motion of the balloon also stops.


收錄日期: 2021-04-29 17:40:34
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101110000051KK00781

檢視 Wayback Machine 備份