Paul wants to share a bag of candies among 15 persons equally, but 3 of them are absent. Therefore, each of the remaining person can get 22 more candies.
find the no.of candies in the bag.
with step please
1 maths文字題
2010-11-10 2:54 am
回答 (3)
2010-11-12 1:48 am
Let x = numbe rof candies in the bag
x/12 = x/15 + 22
x/12 - x/15 = 22
x/60=22
x=1320
x/12 = x/15 + 22
x/12 - x/15 = 22
x/60=22
x=1320
2010-11-11 4:28 am
let y be the no. of candies in the bag
y/(15-3) + (15-3)*22 = y
y/12 + 12*22 = y
y + 12*12*22 = 12y
3168 = 12y-y
11y = 3168
y = 3168/11
y = 288
therefore, the no. of candies in the bag is 288
y/(15-3) + (15-3)*22 = y
y/12 + 12*22 = y
y + 12*12*22 = 12y
3168 = 12y-y
11y = 3168
y = 3168/11
y = 288
therefore, the no. of candies in the bag is 288
參考: girl
2010-11-10 3:04 am
let x be the no.of candies in the bag
x/(15-3)=22
x/12=22
x=264
the no.of candies in the bag are 264
2010-11-09 19:05:01 補充：
.
x/(15-3)=22
x/12=22
x=264
the no.of candies in the bag are 264
2010-11-09 19:05:01 補充：
.
參考: , 魔龍帝齊格益力多
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