Evaluate
∫0 to 2 2^x e^x dx
f4-5 integration
2010-11-10 2:49 am
回答 (2)
2010-11-10 3:57 am
參考: me
2010-11-10 4:25 am
∫ (2^x e^x) dx
=∫ 2^x d(e^x)
=(2^x)(e^x) |[0,2]-∫ (e^x)(2^x)(ln2) dx
=(4e^2-1)-(ln2)∫ (2^x e^x) dx
(1+ln2)(∫ (2^x e^x) dx)=4e^2-1
∫ (2^x e^x) dx =(4e^2-1)/(1+ln2)
=∫ 2^x d(e^x)
=(2^x)(e^x) |[0,2]-∫ (e^x)(2^x)(ln2) dx
=(4e^2-1)-(ln2)∫ (2^x e^x) dx
(1+ln2)(∫ (2^x e^x) dx)=4e^2-1
∫ (2^x e^x) dx =(4e^2-1)/(1+ln2)
收錄日期: 2021-04-26 14:02:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101109000051KK00940