F.5 MATHS...................................
圖片參考：http://imgcld.yimg.com/8/n/HA00002921/o/701011070069213873409640.jpg
F.5 MATHS
2010-11-07 9:43 pm
回答 (1)
2010-11-07 10:29 pm
✔ 最佳答案
(a) Slope of L1=-2/3 =>Slope of L2=3/2The equation of L2 is
(y-2)=(3/2)(x-0)
2y-4=3x
3x-2y+4=0
(b) The intersection point of L1 and L2 is obtained by sloving
2x+3y-19=0
3x-2y+4=0
That is (2,5)
The radius is sqrt[(2-0)^2+(5-2)^2]=sqrt(13)
So C: (x-0)^2+(y-2)^2=13 or x^2+y^2-4y+4=13
收錄日期: 2021-04-26 14:00:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101107000051KK00692