20點!數學超勁難題2^x=x^2數學高手入

2010-11-06 6:35 am
2^x=x^2 請計x的3個值.(需長詳列出步驟)(不能用圖解方法,因為計到唔真確值)
x‧log2=2‧logx 之後點做?or有其他更勁方法?求賜教. 我知有2個解係x=2同4, 但最後個負數解就唔知點計.

回答 (7)

2010-11-12 2:16 am
2^x=x^2
x‧log2=2‧logx
compare the two terms separately, we have
x=2 and log2=log x
so x=2 is one solution

2^x=x^2
take square on both sides
2^2x=x^4
4^x=x^4
same proof as above
x‧log4=4‧logx
compare the two terms separately, we have
x=4 and log4=log x
so x=4 is another solution
2010-11-08 10:50 am
2010-11-07 6:47 am
re:自由自在 ( 知識長 ) x = -0.766664695962123 點解出黎?
re:chung,我識微分,D完之後只計到x=2.牛頓堪根法計咩黎?

2010-11-07 01:49:08 補充:
咁用得圖解法既話,要點做?唔該講解下.如何用牛頓堪根法應用在這題中.
2010-11-07 12:32 am
你識唔識計微分???如果識咁你可以用牛頓堪根法計..

2010-11-06 23:13:46 補充:
對唔住...諗諗下,如果唔用得圖解,應該都唔用得牛頓堪根法,因為牛頓堪根法都唔系準確值,只會隨次數的重複而增加準確值,但唔可以計出0誤差的值....
http://episte.math.ntu.edu.tw/java/jav_newton/index.html
呢個網有講....或者就算牛頓堪根法計唔到準確值,但可以學多d野~~
2010-11-06 9:36 pm
x = -0.766664695962123
2010-11-06 8:50 pm
2^x (not=) x^2

我想講呢到係log唔到2架wor...

When x = 2,
2^(2) = (2)^2
4 = 4
根本就log唔到.
參考: /..\


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