Please help me to slove the following question.
(要詳細步驟)
Factorize the follwoing exprissions
108k+36k^2+3k^3
F.3 Math for factorize
2010-11-04 7:07 am
回答 (3)
2010-11-04 7:10 am
✔ 最佳答案
108k + 36k^2 + 3k^3= 3k (36 + 12k + k^2)= 3k (k^2 + 2(k)(6) + 6^2)= 3k (k + 6)^2 
2010-11-04 9:36 pm
108k+36k^2+3k^3
= 3k (36+12k + k^2)
= 3k [ 6^2 + 2(6)(k) + k^2 ]
= 3k (6+k)^2
= 3k (36+12k + k^2)
= 3k [ 6^2 + 2(6)(k) + k^2 ]
= 3k (6+k)^2
2010-11-04 9:22 pm
108k+36k^2+3k^3
3k(36+12k+k^2)
3k(6+k)^2
3k(36+12k+k^2)
3k(6+k)^2
收錄日期: 2021-04-15 17:18:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101103000051KK01713