The number of births of a city in 2006 was 20000. The number of births of this city decrease by 10% each year.
(a) Find the number of births in 2010
(b) If the number of births is expected to increase by 5% each year from 2013, find the number of births in 2015.( Give your ans correct to the nearest integer.)
ans：(a) 13122 / (b) 12304
exponential function
2010-11-02 2:42 am
回答 (2)
2010-11-02 3:27 am
✔ 最佳答案
(a) Number of birth = 20000(1 - 10%)^4= 13122
(b) Number of birth at 2015 = 20000(1 - 10%)^6(1 + 5%)^3
= 12304
參考: me
2010-11-02 4:34 am
a)The number of births in 2010:20000(1-10%)^4
=13122
∴the number of births in 2010 is 13122
b)The number of births in 2015:20000(1-10%)^6(1+5%)^3
=12304
∴The number of births in 2015 is 12304
=13122
∴the number of births in 2010 is 13122
b)The number of births in 2015:20000(1-10%)^6(1+5%)^3
=12304
∴The number of births in 2015 is 12304
參考: i am teacher
收錄日期: 2021-04-19 23:32:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101101000051KK01070