因式分解
要連式
ax-ay-bx+by
bc+7c-ab-7a
kt-11a+11t-ak
s^2+tv-st-sv
3a^2-b+ab-3a
因式分解 要連式
2010-11-01 4:21 am
回答 (2)
2010-11-01 4:25 am
✔ 最佳答案
ax-ay-bx+by= a(x-y) - b(x-y)
= (a-b)(x-y)
bc+7c-ab-7a
= c(b+7) - a(b+7)
= (c-a)(b+7)
kt-11a+11t-ak
= k(t-a) + 11(t-a)
= (k+11)(t-a)
s^2+tv-st-sv
= s(s-t) - v(s-t)
= (s-v)(s-t)
3a^2-b+ab-3a
= 3a(a-1) + b(a-1)
= (3a+b)(a-1)
參考: Hope the solution can help you^^”
2010-11-01 4:47 am
sol
ax-ay-bx+by
= a(x-y) - b(x-y)
= (a-b)(x-y)
bc+7c-ab-7a
= c(b+7) - a(b+7)
= (c-a)(b+7)
kt-11a+11t-ak
= k(t-a) + 11(t-a)
= (k+11)(t-a)
s^2+tv-st-sv
= s(s-t) - v(s-t)
= (s-v)(s-t)3a^2-b+ab-3a
= 3a(a-1) + b(a-1)
= (3a+b)(a-1)
ax-ay-bx+by
= a(x-y) - b(x-y)
= (a-b)(x-y)
bc+7c-ab-7a
= c(b+7) - a(b+7)
= (c-a)(b+7)
kt-11a+11t-ak
= k(t-a) + 11(t-a)
= (k+11)(t-a)
s^2+tv-st-sv
= s(s-t) - v(s-t)
= (s-v)(s-t)3a^2-b+ab-3a
= 3a(a-1) + b(a-1)
= (3a+b)(a-1)
收錄日期: 2021-04-24 10:32:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101031000051KK01327