數學問題 Change the subject
回答 (3)
2010-11-01 1:24 am
✔ 最佳答案
ax+3 y = b. [y] 因為個subject要係y..所以將唔係y既野放去右面..首先放d唔係痴著y既走
3y=b-ax
y=(b-ax)/3
P = 2(e+w). [e]
2(e+w)=P
e+w=p/2
w=(p/2)-e
T = a + (n-1)d. [n]
T-a=(n-1)d
(T-a)/d=n-1
[T-a)/d]+1=n
n=[(T-a)/d]+1
2010-10-31 17:25:35 補充：
P = 2(e+w). [e]
2(e+w)=P
e+w=p/2
e=(p/2)-w
參考: i am teacher
2010-10-31 11:50 pm
ax+3 y = b. [y]
3y=b-ax
y=(b-ax)/3
P = 2(e+w). [e]
e+w=P/2
e=P/2-w
T = a + (n-1)d. [n]
(n-1)d= T-a
n-1=(T-a)/d
n=(T-a)/d +1
3y=b-ax
y=(b-ax)/3
P = 2(e+w). [e]
e+w=P/2
e=P/2-w
T = a + (n-1)d. [n]
(n-1)d= T-a
n-1=(T-a)/d
n=(T-a)/d +1
收錄日期: 2021-04-13 17:37:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101031000051KK00732