更新1:
To : ☂雨後陽光. Can you please explain why the probability is (1 - 0.2 - 0.1) and not (1 - 0.2) or (1 - 0.1)?
Binomial Distribution
2010-10-31 10:12 pm
A game centre has 80 game machines. Probability of machine requiring repair or replacement is 0.2 and 0.1 respectively. Cost of repair or replacement of a machine is $500 and $4000 respectively. Each machine is independent of each other. What is the probability that the total cost for repair and replacement is $4000? [Ans. 5.218 x 10^(-7)]
回答 (1)
2010-10-31 10:29 pm
✔ 最佳答案
P( total cost for repair and replacement is $4000)= P(8 machines requiring repair) + P(1 machine requiring replacement)= (80C8) (0.2^8) [1 - (0.2+0.1)]^72 + (80C1) (0.1) [1 - (0.2+0.1)]^79= 5.218 x 10^(-7)2010-10-31 23:40:57 補充：
1 - 0.2 : Represent the probability of (No problem or requiring replacement)
1 - 0.1 : Represent the probability of (No problem or requiring repair)
1 - 0.2 - 0.1 : Represent the probability of (No problem)
收錄日期: 2021-04-21 22:17:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101031000051KK00580