In the figure , DC is the diameter of the circle BDC . ABC and EDC are straight lines . Find ∠EBA+∠DAE
圖片參考：http://img209.imageshack.us/img209/7272/93096298.png
circle!!
2010-10-30 1:14 am
回答 (1)
2010-10-30 1:44 am
✔ 最佳答案
∠DBE = ∠DAE (∠ in the same segment)∠CBD = 90 deg (∠ in semi-circle)
∠DBA = 180 deg - ∠CBD (adj. ∠s on st.line)
= 180 deg - 90 deg
= 90 deg
∠EBA + ∠DBE = 90 deg
∠EBA = ∠DAE = 90 deg
參考: Knowledge is power.
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原文連結 [永久失效]:
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