因式分解要連式

3a-bd+ad-3b
= 3a-3b+ad-bd
= 3(a-b)+d(a-b)
= (3-d)(a-b)

ab+2c-2b-ac
= ab-2b-ac+2c
= b(a-2)-c(a-2)
= (b-c)(a-2)

x^2+2x+ad-3b
=> 有冇寫錯?

a^2+2ab-6b-3a
=a^2-3a+2ab-6b
=a(a-3)+2b(a-3)
=(a+2b)(a-3)

x^2x-4y+2xy
=> 有冇寫錯?

x^-ay+ax-xy
=x^2+ax-xy-ay
=x(x+a)-y(x+a)
=(x-y)(x+a)

3a-bd+ad-3b=3a-3b-bd+ad=3(a-b)-d(b+a)=-3(a+b)-d(b+a)
ab+2c-2b-ac=2c-ac+ ab-2b=c(2-a)+b(a-2)=c(-a+2)+b(a-2)=-C(a-2)+ (a-2)=(c+1) (a-2)

+2x+ad-3b=x(x+2) +ad-3b
+2ab-6b-3a=-3a+2ab-6b=a(a-3)+2b(a-3)=(a+2b) (a-3)
-4y+2xy=+2Y-4Y-2Y
+ax-xy-X(A+Y)

2010-10-27 20:59:27 補充：
X^2+2x+ad-3b
=x(x+2) +ad-3b


a^2+2ab-6b-3a
=a^2-3a+2ab-6b
=a(a-3)+2b(a-3)
=(a+2b) (a-3)

X^2X-4y+2xy
=X^(2X-1)+2Y-4Y
X^(2X-1)-2Y

X^(-ay)+ax-xy
X^(-ay)-X(A+Y)

3a-bd+ad-3b
=3a-3b+ad-bd
=(3+d)(a-b)

ab+2c-2b-ac
=ab-ac-2b+2c
=a(b-c)-2(b-c)
=(a-2)(b-c)

a^2+2ab-6b-3a
=a^2-3a+2ab-6b
=a(a-3)+2b(a-3)
=(a+2b)(a-3)

恕本人只能幹至如此,請另覓高人。