20點!!急!!!(f.2 代數分式/公式 )

m = (1 - 2t) / (1 + 2t)m(1 + 2t) = 1 - 2tm + 2tm = 1 - 2t2t + 2tm = 1 - m2t(1 + m) = 1 - mt = (1 - m)/(2 + 2m);n = (1 - t) / [2( t + 1)]n = [1 - (1 - m)/(2 + 2m)] / [2 ( (1 - m)/(2 + 2m) + 1 )]n = [(3m + 1)/(2m + 2)] / [2 (m + 3)/(2m + 2)]n = (3m + 1) / [2(m + 3)]n = (3m + 1) / (2m + 6)


2010-10-26 22:50:20 補充：
我想確認一下題目 ,

是 m = 1 - [2t / (1+2t)]

n = 1 - [t / (2( t + 1))] 嗎?

2010-10-26 23:54:52 補充：
m = (1 - 2t) / (1 + t)

m(1 + t) = 1 - 2t

m + mt = 1 - 2t

(m+2)t = 1 - m

t = (1 - m)/(m + 2)

;

n = 1 - t / [2 ( t + 1)]

n = [ 1 - (1 - m)/(m + 2) ] / [ 2 [(1 - m)/(m + 2) + 1] ]

n = [(2m + 1)/(m + 2)] / [ 2 [3/(m + 2)] ]

n = (2m + 1) / 6

☂雨後陽光☀ ( 知識長 )解答正確