circle 急!!!

2010-10-27 3:49 am

In the figure , AB and CD are equal chords . BC and AD intersect at E.
Prove that 三角形ABE 全等於三角形CDE.

圖片參考：http://img36.imageshack.us/img36/1318/88848710.png

回答 (3)

2010-10-27 3:57 am

✔ 最佳答案

Sol
在△ABE與△CDE中
AB=CD (AB弧=CD弧)
∠AEB=∠CED(對角)
∠ABE=(1/2)AB弧=∠CDE
So
△ABE全等於△CDE中(AAS)

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2010-10-27 4:28 am

Join AC or join BD.
You will see angles in the same segment

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2010-10-27 3:58 am

ab=cd (given)
angle aeb = angle ced (vert opp angles)
angle abe = angle cda (angles in the same segment)
AAS

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