In the figure , AB and CD are equal chords . BC and AD intersect at E.
Prove that 三角形ABE 全等於三角形CDE.
圖片參考：http://img36.imageshack.us/img36/1318/88848710.png
circle 急!!!
2010-10-27 3:49 am
回答 (3)
2010-10-27 3:57 am
✔ 最佳答案
Sol在△ABE與△CDE中
AB=CD (AB弧=CD弧)
∠AEB=∠CED(對角)
∠ABE=(1/2)AB弧=∠CDE
So
△ABE全等於△CDE中(AAS)
2010-10-27 4:28 am
Join AC or join BD.
You will see angles in the same segment
You will see angles in the same segment
2010-10-27 3:58 am
ab=cd (given)
angle aeb = angle ced (vert opp angles)
angle abe = angle cda (angles in the same segment)
AAS
angle aeb = angle ced (vert opp angles)
angle abe = angle cda (angles in the same segment)
AAS
收錄日期: 2021-04-19 23:30:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20101026000051KK01293