EASY MATHS (QUICK!!!!!!!!!!!!!

z = 4[cos(兀/3)+isin(兀/3)]
= 2 + (2sqrt3)i

w = -4+4i
= 4sqrt2[-1/sqrt2 + i/sqrt2]
= 4sqrt2[cos(3兀/4) + isin(3兀/4)]

2010-10-25 19:24:02 補充：
z = a + bi
Use the formula
丨z丨 = sqrt(a^2 + b^2)
arg(z) = b/a

You can finish z by direct multiplication.
For w, modulus = sqrt(4^2 + 4^2) = 4sqrt2
arg(w) = (1/sqrt2) / (-1/sqrt2) = -1
w = 3兀/4

2010-10-25 19:25:57 補充：
sorry, arg(w) = arctan[(1/sqrt2) / (-1/sqrt2)]
arg(w) = 3兀/4

can u show more workings, i still don't understand how to get them!