If c=5over9(F-32),find F
1 over n-3減1 over n-3
maths x2(need step)
2010-10-25 9:06 am
回答 (2)
2010-10-25 3:17 pm
✔ 最佳答案
c=5/9(F-32)9(F-32) = 5/c
F-32 = 5/9c
F = 5/9c + 32
[1/(n-3-1)]/(n-3)
= (n-3)/(n-4)
or
1/(n-3) - 1/(n-3)
= 0
參考: Hope the solution can help you^^”
2010-10-26 2:25 am
C = 5(F-32)/9
9C = 5F-5*32
5F = 9C+160
F = (9C+160)/5
F = 9C/5 + 32
1/(n-3) - 1/(n-3)
= 0
9C = 5F-5*32
5F = 9C+160
F = (9C+160)/5
F = 9C/5 + 32
1/(n-3) - 1/(n-3)
= 0
收錄日期: 2021-04-23 23:13:56
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